What is ground state?
(N/A) The ground state of an atom is the lowest energy state of the system.
In the context of the Bohr model for a hydrogen atom,it corresponds to the state where the electron is in the innermost orbit,which is the orbit with the principal quantum number $n = 1$.
The energy of the electron in the ground state of a hydrogen atom is approximately $-13.6 \ eV$.
In the context of the Bohr model for a hydrogen atom,it corresponds to the state where the electron is in the innermost orbit,which is the orbit with the principal quantum number $n = 1$.
The energy of the electron in the ground state of a hydrogen atom is approximately $-13.6 \ eV$.
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In the first excited state of a hydrogen atom, the energy of its electron is $-3.4 \text{ eV}$. The radial distance of the electron from the hydrogen nucleus in this case is approximately: (Take $1 \text{ eV} = 1.6 \times 10^{-19} \text{ J}$, $e = 1.6 \times 10^{-19} \text{ C}$ and $\frac{1}{4\pi\epsilon_0} = 9 \times 10^9 \text{ N m}^2/\text{C}^2$)
MediumNEET 2026
View SolutionIf the radius of the first orbit of an $H$ atom is $a_0$, then the de Broglie wavelength of an electron in the third orbit is: (in $\pi a_0$)
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View SolutionFor principal quantum number $n = 3$,the possible values of orbital quantum number $l$ are
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View Solution$A$ monochromatic radiation of wavelength $\lambda$ is incident on a hydrogen sample in ground state. The sample subsequently emits radiation of six different wavelengths, then the value of $\lambda$ is. [Use $hc = 1242 \text{ eV-nm}$] (in $\text{ nm}$)
The ratio of wavelengths for the transition of electrons from the $2^{nd}$ orbit to the $1^{st}$ orbit of Helium $(He^+)$ and Lithium $(Li^{++})$ is (Atomic number of Helium = $2$,Atomic number of Lithium = $3$).
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