What is increased in a step-down transformer?

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(B) In an ideal transformer,the power remains constant,meaning $P_p = P_s$,which implies $V_p I_p = V_s I_s$.For a step-down transformer,the secondary

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(B) In an ideal transformer,the power remains constant,meaning $P_p = P_s$,which implies $V_p I_p = V_s I_s$.For a step-down transformer,the secondary voltage is less than the primary voltage,i.e.,$V_s Since $V_p I_p = V_s I_s$,we have $\frac{V_p}{V_s} = \frac{I_s}{I_p}$.Because $V_p > V_s$,it follows that $I_s > I_p$.Therefore,the current in the secondary coil is increased compared to the primary coil.

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