What is the kinetic energy of 1,g of O_2 at 4 | vedclass

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(A) The formula for the total kinetic energy of an ideal gas is $K.E. = \frac{3}{2} nRT$.Given mass $m = 1\,g$,molar mass of $O_2$ $M = 32\,g/mol$,and

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$1.24 	imes 10^2\,J$

Vedclass · Answer

(A) The formula for the total kinetic energy of an ideal gas is $K.E. = \frac{3}{2} nRT$.Given mass $m = 1\,g$,molar mass of $O_2$ $M = 32\,g/mol$,and temperature $T = 47 + 273 = 320\,K$.The number of moles $n = \frac{m}{M} = \frac{1}{32}\,mol$.Substituting the values: $K.E. = \frac{3}{2} 	imes \frac{1}{32} 	imes 8.314 	imes 320\,J$.$K.E. = \frac{3}{2} 	imes 8.314 	imes 10 = 1.5 	imes 83.14 = 124.71\,J$.Rounding to the nearest provided option,we get $1.24 	imes 10^2\,J$.

What is the kinetic energy of $1\,g$ of $O_2$ at $47\,^{\circ}C$?

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