What is the range of a projectile? Also,provide the velocity of the projectile at its maximum height.

(N/A) The range $R$ of a projectile is given by the formula: $R = \frac{v_{0}^2 \sin(2\theta_{0})}{g}$,where $v_{0}$ is the initial velocity,$\theta_{0}$ is the angle of projection,and $g$ is the acceleration due to gravity.
At the maximum height,the vertical component of the velocity becomes zero $(v_{y} = 0)$.
Therefore,the velocity of the projectile at the maximum height is equal to its horizontal component: $v = v_{x} = v_{0} \cos \theta_{0}$.