What is the specific heat of a gas in an isothermal process and an adiabatic process?
(A) For an isothermal process,the temperature change $\Delta T = 0$. Since the specific heat is defined as $C = \frac{\Delta Q}{m \Delta T}$,as $\Delta T \to 0$,the specific heat $C$ becomes infinite.
For an adiabatic process,there is no heat exchange with the surroundings,so $\Delta Q = 0$. Substituting this into the formula $C = \frac{\Delta Q}{m \Delta T}$,we get $C = 0$.
For an adiabatic process,there is no heat exchange with the surroundings,so $\Delta Q = 0$. Substituting this into the formula $C = \frac{\Delta Q}{m \Delta T}$,we get $C = 0$.
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Similar Questions
Match the following:
List-$I$ List-$II$ $i)$ Isothermal process $a)$ $0$ $ii)$ Isobaric process $b)$ $\frac{1}{\gamma-1}[P_2 V_2 - P_1 V_1]$ $iii)$ Isochoric process $c)$ $\mu RT \ln(\frac{V_2}{V_1})$ $iv)$ Adiabatic process $d)$ $P(V_2 - V_1)$
The correct answer is:
| List-$I$ | List-$II$ |
| $i)$ Isothermal process | $a)$ $0$ |
| $ii)$ Isobaric process | $b)$ $\frac{1}{\gamma-1}[P_2 V_2 - P_1 V_1]$ |
| $iii)$ Isochoric process | $c)$ $\mu RT \ln(\frac{V_2}{V_1})$ |
| $iv)$ Adiabatic process | $d)$ $P(V_2 - V_1)$ |
The correct answer is:
$A$ gas is compressed isothermally to half its initial volume. The same gas is compressed separately through an adiabatic process until its volume is again reduced to half. Then
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$(i)$ What is $W$ along path $ibf$?
$(ii)$ If $W = -13 \, cal$ for path $fi$,what is $Q$ for the path $fi$?
$(iii)$ Take $E_{int,i} = 10 \, cal$,then what is $E_{int,f}$?
$(i)$ What is $W$ along path $ibf$?
$(ii)$ If $W = -13 \, cal$ for path $fi$,what is $Q$ for the path $fi$?
$(iii)$ Take $E_{int,i} = 10 \, cal$,then what is $E_{int,f}$?
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View SolutionWhat is an isochoric process and a cyclic process? Write the first law of thermodynamics for an ideal gas.
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