What is the pH value of a 1 times 10^{-5} ; M | vedclass

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(C) $NaOH$ is a strong base that dissociates completely in water as follows:$NaOH ightarrow Na^+ + OH^-$Given the concentration of $NaOH$ is $1 	im

Vedclass · Accepted Answer

$9$

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(C) $NaOH$ is a strong base that dissociates completely in water as follows:$NaOH ightarrow Na^+ + OH^-$Given the concentration of $NaOH$ is $1 	imes 10^{-5} \; M$,the concentration of $OH^-$ ions $[OH^-]$ is $1 	imes 10^{-5} \; M$.We know that $pOH = -\log[OH^-]$.$pOH = -\log(1 	imes 10^{-5}) = 5$.Using the relation $pH + pOH = 14$ at $25^{\circ}C$:$pH = 14 - pOH = 14 - 5 = 9$.Therefore,the $pH$ of the solution is $9$.

What is the $pH$ value of a $1 \times 10^{-5} \; M$ aqueous solution of $NaOH$?

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