What is the binding energy of { }_{14}^{29} S | vedclass

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(A) The atomic number $Z = 14$ and the mass number $A = 29$.The number of protons is $Z = 14$.The number of neutrons is $N = A - Z = 29 - 14 = 15$.The

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$237.86$

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(A) The atomic number $Z = 14$ and the mass number $A = 29$.The number of protons is $Z = 14$.The number of neutrons is $N = A - Z = 29 - 14 = 15$.The mass defect $\Delta m$ is given by $\Delta m = [Z m_p + N m_n] - M_{nucleus}$.$\Delta m = [14 	imes 1.007276 u + 15 	imes 1.008664 u] - 28.976495 u$.$\Delta m = [14.101864 u + 15.129960 u] - 28.976495 u$.$\Delta m = 29.231824 u - 28.976495 u = 0.255329 u$.The binding energy $B.E. = \Delta m 	imes 931.5 MeV/u$.$B.E. = 0.255329 	imes 931.5 MeV \approx 237.84 MeV$.Rounding to the nearest provided option, the correct answer is $237.86 MeV$.

What is the binding energy of ${ }_{14}^{29} Si$ whose atomic mass is $28.976495 u$ (in $MeV$)?
Mass of proton $= 1.007276 u$
Mass of neutron $= 1.008664 u$
(Neglect the electron mass) (Assume $1 u = 931.5 MeV$)

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What is the binding energy of ${ }_{14}^{29} Si$ whose atomic mass is $28.976495 u$ (in $MeV$)?Mass of proton $= 1.007276 u$Mass of neutron $= 1.008664 u$(Neglect the electron mass) (Assume $1 u = 931.5 MeV$)