What is the chance that a leap year,selected | vedclass

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(B) leap year consists of $366$ days,which is equivalent to $52$ weeks and $2$ extra days.The possible combinations for these $2$ extra days are:$(i)$

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$2$

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(B) leap year consists of $366$ days,which is equivalent to $52$ weeks and $2$ extra days.The possible combinations for these $2$ extra days are:$(i)$ Sunday and Monday$(ii)$ Monday and Tuesday$(iii)$ Tuesday and Wednesday$(iv)$ Wednesday and Thursday$(v)$ Thursday and Friday$(vi)$ Friday and Saturday$(vii)$ Saturday and SundayTotal number of exhaustive cases $n = 7$.For the year to have $53$ Sundays,one of the $2$ extra days must be a Sunday. The favourable cases are $(i)$ (Sunday and Monday) and $(vii)$ (Saturday and Sunday).Number of favourable cases $m = 2$.Therefore,the probability of having $53$ Sundays is $P = m/n = 2/7$.

What is the chance that a leap year,selected at random,will contain $53$ Sundays (in $/7$)?

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