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(B) In an adiabatic process,there is no exchange of heat between the system and the surroundings,so $dQ = 0$.According to the first law of thermodynam

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Temperature decreases

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(B) In an adiabatic process,there is no exchange of heat between the system and the surroundings,so $dQ = 0$.According to the first law of thermodynamics,$dQ = dU + dW$,where $dU$ is the change in internal energy and $dW$ is the work done.Since $dQ = 0$,we have $0 = dU + dW$,which implies $dU = -dW$.When work is done by the gas,$dW > 0$.Therefore,$dU = -dW Since the internal energy of an ideal gas is directly proportional to its temperature $(U \propto T)$,a decrease in internal energy leads to a decrease in the temperature of the gas.

What is the change in temperature when work is done by a gas in an adiabatic process?

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