What is the concentration of sugar (C_{12}H_{ | vedclass

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(A) Molarity $(M)$ of a solution is defined as the number of moles of solute per liter of solution.$M = \frac{	ext{Number of moles of solute}}{	ext{

Vedclass · Accepted Answer

$0.02925 \ mol \ L^{-1}$

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(A) Molarity $(M)$ of a solution is defined as the number of moles of solute per liter of solution.$M = \frac{	ext{Number of moles of solute}}{	ext{Volume of solution in Litres}}$First,calculate the molar mass of sugar $(C_{12}H_{22}O_{11})$:$Molar \ mass = (12 	imes 12) + (1 	imes 22) + (11 	imes 16) = 144 + 22 + 176 = 342 \ g \ mol^{-1}$Next,calculate the number of moles of sugar:$Moles = \frac{	ext{Mass}}{	ext{Molar mass}} = \frac{20 \ g}{342 \ g \ mol^{-1}} \approx 0.05848 \ mol$Finally,calculate the molarity:$M = \frac{0.05848 \ mol}{2 \ L} = 0.02924 \ mol \ L^{-1} \approx 0.02925 \ mol \ L^{-1}$

What is the concentration of sugar $(C_{12}H_{22}O_{11})$ in $mol \ L^{-1}$ if its $20 \ g$ are dissolved in enough water to make a final volume up to $2 \ L$?

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