What is the conductivity of $0.02 \ M$ $AgNO_3$ solution having cell constant $1.1 \ cm^{-1}$ and resistance $94.5 \ \Omega$?

$A$ $KCl$ solution of conductivity $0.14 \, S m^{-1}$ shows a resistance of $4.19 \, \Omega$ in a conductivity cell. If the same cell is filled with an $HCl$ solution,the resistance drops to $1.03 \, \Omega$. The conductivity of the $HCl$ solution is $....... \, \times 10^{-2} \, S m^{-1}$. (Round off to the Nearest Integer).

An increase in molar conductance of a strong electrolyte with dilution is mainly due to

The molar conductances of $Ba(OH)_2$, $BaCl_2$ and $NH_4Cl$ at infinite dilution are $523.28$, $280.0$ and $129.8 \ S \ cm^2 \ mol^{-1}$ respectively. The molar conductance of $NH_4OH$ at infinite dilution will be:

If $X$ is the specific resistance (resistivity) of the solution and $M$ is the molarity of the solution,the molar conductivity of the solution is given by:

Match List-$I$ with List-$II$:

List-$I$ (Parameter)	List-$II$ (Unit)
$a$. Cell constant	$i$. $S\, cm^{2}\, mol^{-1}$
$b$. Molar conductivity	$ii$. Dimensionless
$c$. Conductivity	$iii$. $m^{-1}$
$d$. Degree of dissociation of electrolyte	$iv$. $\Omega^{-1}\, m^{-1}$

Choose the most appropriate answer from the options given below: