What is the correct order of spin only magnet | vedclass

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Question

(C) Spin only magnetic moments depend upon the number of unpaired electrons; the greater the number of unpaired electrons,the greater will be the spin

Vedclass · Accepted Answer

$Mn^{2+} > Cr^{2+} > V^{2+}$

Vedclass · Answer

(C) Spin only magnetic moments depend upon the number of unpaired electrons; the greater the number of unpaired electrons,the greater will be the spin only magnetic moment.$Mn$ $(Z=25)$: $[Ar] 3d^5 4s^2$$Mn^{2+}$: $[Ar] 3d^5$,number of unpaired electrons = $5$$Cr$ $(Z=24)$: $[Ar] 3d^5 4s^1$$Cr^{2+}$: $[Ar] 3d^4$,number of unpaired electrons = $4$$V$ $(Z=23)$: $[Ar] 3d^3 4s^2$$V^{2+}$: $[Ar] 3d^3$,number of unpaired electrons = $3$Since the magnetic moment $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons,the order of magnetic moment is $Mn^{2+} > Cr^{2+} > V^{2+}$.

What is the correct order of spin only magnetic moment (in $BM$) of $Mn^{2+}, Cr^{2+}$ and $V^{2+}$?

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