What is the difference in molar masses of the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The general formula for the alkane series is $C_nH_{2n+2}$.For the third homologue $(n=3)$,the formula is $C_3H_8$,and its molar mass is $(3 	ime

Vedclass · Accepted Answer

$14 \ g \ mol^{-1}$

Vedclass · Answer

(B) The general formula for the alkane series is $C_nH_{2n+2}$.For the third homologue $(n=3)$,the formula is $C_3H_8$,and its molar mass is $(3 	imes 12) + (8 	imes 1) = 44 \ g \ mol^{-1}$.For the fourth homologue $(n=4)$,the formula is $C_4H_{10}$,and its molar mass is $(4 	imes 12) + (10 	imes 1) = 58 \ g \ mol^{-1}$.Any two successive homologues in an alkane series differ by a $-CH_2-$ group.The molar mass of a $-CH_2-$ group is $12 + (2 	imes 1) = 14 \ g \ mol^{-1}$.Therefore,the difference in molar masses is $58 - 44 = 14 \ g \ mol^{-1}$.

What is the difference in molar masses of the third and fourth homologues of the alkane series?

Similar Questions

Which of the following obtained products is not correct?

Isomerism in saturated hydrocarbons is due to

What is the number of moles of secondary carbon atoms in $n \ mol$ of isopentane?

In which of the following reactions is the product a hydrocarbon?

The reaction conditions leading to the best yields of $C_2H_5Cl$ are

Vedclass Test Series

Exam Paper Generator

Online Exam Module