What is the effect of the reduction of the vo | vedclass

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(A) According to $Le \ Chatelier's \ Principle$,when the volume of a system at equilibrium is reduced,the pressure increases. To counteract this incre

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The equilibrium will be shifted to the left by the increased pressure caused by the reduction in volume.

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(A) According to $Le \ Chatelier's \ Principle$,when the volume of a system at equilibrium is reduced,the pressure increases. To counteract this increase in pressure,the system shifts in the direction that produces fewer moles of gas. In the reaction $2 C_{(s)} + O_{2(g)} \rightleftharpoons 2 CO_{(g)}$,the number of moles of gaseous reactants is $1$ $(O_{2})$ and the number of moles of gaseous products is $2$ $(CO)$. Since the number of moles of gaseous products $(2)$ is greater than the number of moles of gaseous reactants $(1)$,an increase in pressure (due to volume reduction) will shift the equilibrium to the left (towards the reactants) to decrease the total number of gas moles.

What is the effect of the reduction of the volume of the system for the equilibrium $2 C_{(s)} + O_{2(g)} \rightleftharpoons 2 CO_{(g)}$?

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