What is the expression for the solubility pro | vedclass

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Question

(C) The dissociation of silver chromate $(Ag_2CrO_4)$ in water is represented as:
$Ag_2CrO_{4(s)} \rightleftharpoons 2Ag^+{(aq)} + CrO_4^{2-}{(aq)}$

Vedclass · Accepted Answer

$4S^3$

Vedclass · Answer

(C) The dissociation of silver chromate $(Ag_2CrO_4)$ in water is represented as:
$Ag_2CrO_{4(s)} ightleftharpoons 2Ag^+{(aq)} + CrO_4^{2-}{(aq)}$
If the solubility is $S \ mol \ L^{-1}$,the concentration of ions at equilibrium will be:
$[Ag^+] = 2S \ mol \ L^{-1}$
$[CrO_4^{2-}] = S \ mol \ L^{-1}$
The solubility product $(K_{sp})$ is defined as:
$K_{sp} = [Ag^+]^2 [CrO_4^{2-}]$
Substituting the values:
$K_{sp} = (2S)^2 	imes (S)$
$K_{sp} = 4S^2 	imes S = 4S^3$

What is the expression for the solubility product of silver chromate $(Ag_2CrO_4)$ if its solubility is expressed as $S \ mol \ L^{-1}$?

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