What is the formal charge on sulfur in the fo | vedclass

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(C) The formula for formal charge $(FC)$ is: $FC = V.E. - N.E. - \frac{1}{2}(B.E.)$Where $V.E.$ is the number of valence electrons,$N.E.$ is the numbe

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(C) The formula for formal charge $(FC)$ is: $FC = V.E. - N.E. - \frac{1}{2}(B.E.)$Where $V.E.$ is the number of valence electrons,$N.E.$ is the number of non-bonding electrons,and $B.E.$ is the number of bonding electrons.For sulfur $(S)$ in the given structure:Valence electrons $(V.E.)$ = $6$Non-bonding electrons $(N.E.)$ = $0$Bonding electrons $(B.E.)$ = $12$ (six bonds: two double bonds and two single bonds)$FC = 6 - 0 - \frac{1}{2}(12) = 6 - 6 = 0$

What is the formal charge on sulfur in the following Lewis structure?

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