Class 11Physics1 Thermal Properties of Matter: Thermometry, Expansion and CalorimetryHeat Capacity, Specific Heat and Molar Specific Heat
EasyWhat is the heat capacity of copper of $40 \, g$ and specific heat $0.3 \, erg \, g^{-1} (^{\circ} C)^{-1}$?
$(12 \, erg (^{\circ} C)^{-1})$ The heat capacity $C$ is defined as the product of the mass $m$ and the specific heat capacity $s$ of the substance.
Given:
Mass $m = 40 \, g$
Specific heat $s = 0.3 \, erg \, g^{-1} (^{\circ} C)^{-1}$
Calculation:
$C = m \times s$
$C = 40 \, g \times 0.3 \, erg \, g^{-1} (^{\circ} C)^{-1}$
$C = 12 \, erg (^{\circ} C)^{-1}$
Given:
Mass $m = 40 \, g$
Specific heat $s = 0.3 \, erg \, g^{-1} (^{\circ} C)^{-1}$
Calculation:
$C = m \times s$
$C = 40 \, g \times 0.3 \, erg \, g^{-1} (^{\circ} C)^{-1}$
$C = 12 \, erg (^{\circ} C)^{-1}$
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