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(C) The reaction of chlorobenzene with fused $NaOH$ at high temperature $(623 \ K)$ and high pressure $(300 \ atm)$ is known as the Dow process.The re

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Sodium phenoxide

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(C) The reaction of chlorobenzene with fused $NaOH$ at high temperature $(623 \ K)$ and high pressure $(300 \ atm)$ is known as the Dow process.The reaction proceeds as follows:$C_6H_5Cl + 2NaOH \rightarrow C_6H_5ONa + NaCl + H_2O$In this reaction,chlorobenzene reacts with fused $NaOH$ to form sodium phenoxide $(C_6H_5ONa)$ as the intermediate product.Subsequently,acidification of sodium phenoxide yields phenol.Therefore,the intermediate compound formed is sodium phenoxide.

What is the intermediate compound formed when chlorobenzene is treated with fused $NaOH$ under pressure?

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