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(A) The reaction proceeds in two steps: $1$. The ketone reacts with methylamine $(CH_3NH_2)$ to form an imine intermediate $(R_2C=NCH_3)$. $2$. The im

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$N$-methyl$-2-$propanamine

Vedclass · Answer

(A) The reaction proceeds in two steps: $1$. The ketone reacts with methylamine $(CH_3NH_2)$ to form an imine intermediate $(R_2C=NCH_3)$. $2$. The imine is then reduced by lithium aluminum hydride $(LiAlH_4)$ followed by hydrolysis $(H_2O)$ to yield a secondary amine,specifically $N$-methyl$-2-$propanamine.

What is the major product obtained from the following reaction?

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