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(B) The reaction of $1	ext{-methylcyclopentene}$ with $	ext{HBr}$ in the presence of peroxide follows the anti-Markovnikov addition mechanism (Khara

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$2-$bromo$-1-$methylcyclopentane

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(B) The reaction of $1	ext{-methylcyclopentene}$ with $	ext{HBr}$ in the presence of peroxide follows the anti-Markovnikov addition mechanism (Kharasch effect or peroxide effect).In this mechanism,the bromine atom $(	ext{Br}^\bullet)$ adds to the carbon atom of the double bond that has more hydrogen atoms (or less substituted carbon),while the hydrogen atom adds to the other carbon.For $1	ext{-methylcyclopentene}$,the double bond is between $C_1$ (substituted with a methyl group) and $C_2$ (which has one hydrogen atom).According to the anti-Markovnikov rule,the $	ext{Br}$ atom will attach to the $C_2$ position,resulting in $2	ext{-bromo-1-methylcyclopentane}$ as the major product.

Reaction	Product
$I$. $RX + AgCN$	$RNC$
$II$. $RX + KCN$	$RCN$
$III$. $RX + KNO_2$	$RONO$
$IV$. $RX + AgNO_2$	$RNO_2$

What is the major product of the following reaction?
$1\text{-methylcyclopentene} \xrightarrow[\text{Peroxide}]{\text{HBr}} ?$

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Reaction Product

$I$. $RX + AgCN$ $RNC$

$II$. $RX + KCN$ $RCN$

$III$. $RX + KNO_2$ $RONO$

$IV$. $RX + AgNO_2$ $RNO_2$

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What is the major product of the following reaction?$1\text{-methylcyclopentene} \xrightarrow[\text{Peroxide}]{\text{HBr}} ?$