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(B) To obtain the maximum resistance from a given set of resistors,they must be connected in series.In a series connection,the equivalent resistance $

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$1$

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(B) To obtain the maximum resistance from a given set of resistors,they must be connected in series.In a series connection,the equivalent resistance $(R_{eq})$ is the sum of individual resistances.Given that there are $n = 5$ resistors,each with a resistance of $R = 1/5 \ \Omega$.The formula for equivalent resistance in series is $R_{eq} = R_1 + R_2 + R_3 + R_4 + R_5$.Substituting the values: $R_{eq} = 1/5 + 1/5 + 1/5 + 1/5 + 1/5 = 5 	imes (1/5) = 1 \ \Omega$.Therefore,the maximum resistance is $1 \ \Omega$.

What is the maximum resistance which can be made using five resistors each of $1/5 \ \Omega$ (in $\Omega$)?

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