What is the molar solubility of Ag_{2}CO_{3} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The dissociation of $Ag_{2}CO_{3}$ is given by: $Ag_{2}CO_{3(s)} \longleftrightarrow 2Ag^{+}_{(aq)} + C{O_{3}}^{2-}_{(aq)}$In the presence of $0.1

Vedclass · Accepted Answer

$10^{-6}$

Vedclass · Answer

(A) The dissociation of $Ag_{2}CO_{3}$ is given by: $Ag_{2}CO_{3(s)} \longleftrightarrow 2Ag^{+}_{(aq)} + C{O_{3}}^{2-}_{(aq)}$In the presence of $0.1 \ M \ Na_{2}CO_{3}$,the concentration of $CO_{3}^{2-}$ is dominated by the salt,so $[CO_{3}^{2-}] \approx 0.1 \ M$.Let $s$ be the molar solubility of $Ag_{2}CO_{3}$. Then $[Ag^{+}] = 2s$.The solubility product expression is $K_{sp} = [Ag^{+}]^{2} [CO_{3}^{2-}]$.Substituting the values: $4 	imes 10^{-13} = (2s)^{2} 	imes (0.1)$.$4 	imes 10^{-13} = 4s^{2} 	imes 0.1$.$10^{-13} = s^{2} 	imes 10^{-1}$.$s^{2} = 10^{-12}$.$s = 10^{-6} \ M$.

What is the molar solubility of $Ag_{2}CO_{3}$ $(K_{sp} = 4 \times 10^{-13})$ in $0.1 \ M \ Na_{2}CO_{3}$ solution?

Similar Questions

An ionic compound is dissolved simultaneously in heavy water and simple water. Its solubility is

Two salts $A_2X$ and $MX$ have the same value of solubility product of $4.0 \times 10^{-12}$. The ratio of their molar solubilities i.e. $\frac{S(A_2X)}{S(MX)} = \dots$ (Round off to the Nearest Integer).

The solubility of $BaSO_4$ in pure water (in $g \, L^{-1}$) is closest to
[Given: $K_{sp}$ for $BaSO_4$ is $1.0 \times 10^{-10}$ at $25^{\circ} C$. Molecular weight of $BaSO_4$ is $233 \, g \, mol^{-1}$]

The solubility product of $AgCl$ at $25 \, ^\circ C$ is $5 \times 10^{-13}$. Its solubility is = .......

The solubility product of a sparingly soluble salt $AX_2$ is $3.2 \times 10^{-11}$. Its solubility (in moles/litres) is

Vedclass Test Series

Exam Paper Generator

Online Exam Module