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(A) When a mixture of two different aldehydes (ethanal and propanal),both containing at least one $\alpha$-hydrogen,reacts with aqueous $NaOH$ and is

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$4$

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(A) When a mixture of two different aldehydes (ethanal and propanal),both containing at least one $\alpha$-hydrogen,reacts with aqueous $NaOH$ and is warmed,it undergoes a cross-aldol condensation reaction.Each aldehyde can undergo self-aldol condensation,and they can also undergo cross-aldol condensation with each other.$1$. Self-aldol of ethanal: $CH_3CHO + CH_3CHO \rightarrow CH_3CH=CHCHO$ (after dehydration).$2$. Self-aldol of propanal: $CH_3CH_2CHO + CH_3CH_2CHO \rightarrow CH_3CH_2CH=C(CH_3)CHO$ (after dehydration).$3$. Cross-aldol (ethanal as donor,propanal as acceptor): $CH_3CHO + CH_3CH_2CHO \rightarrow CH_3CH=C(CH_3)CHO$ (after dehydration).$4$. Cross-aldol (propanal as donor,ethanal as acceptor): $CH_3CH_2CHO + CH_3CHO \rightarrow CH_3CH_2CH=CHCHO$ (after dehydration).Thus,a total of $4$ different aldol condensation products are formed.

List-$I$	List-$II$
$(a)$ $NH_2OH$	$(i)$ Cyanohydrin
$(b)$ $R-NH_2$	(ii) Oxime
$(c)$ $R-OH$	(iii) Schiff base
$(d)$ $H-C\equiv N$	(iv) Acetal

What is the number of different products formed when a mixture of ethanal and propanal reacts with aqueous $NaOH$ after warming?

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