(D) For the molecule $Na_2S_4O_6$,let the oxidation number of sulphur be $x$.Assigning oxidation states: $Na = +1$,$O = -2$.The sum of oxidation state

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(D) For the molecule $Na_2S_4O_6$,let the oxidation number of sulphur be $x$.Assigning oxidation states: $Na = +1$,$O = -2$.The sum of oxidation states in a neutral molecule is $0$.$2(+1) + 4(x) + 6(-2) = 0$$2 + 4x - 12 = 0$$4x - 10 = 0$$4x = 10$$x = 10/4 = 5/2$Therefore,the average oxidation number of sulphur is $5/2$.