What is the oxidation state of sulphur in oil | vedclass

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Question

(B) The chemical name for oil of vitriol is sulphuric acid,which has the formula $H_2SO_4$. To find the oxidation state of sulphur $(S)$,let it be $x$

Vedclass · Accepted Answer

$+6$

Vedclass · Answer

(B) The chemical name for oil of vitriol is sulphuric acid,which has the formula $H_2SO_4$. To find the oxidation state of sulphur $(S)$,let it be $x$. The oxidation state of hydrogen $(H)$ is $+1$ and oxygen $(O)$ is $-2$. Setting the sum of oxidation states to zero: $2(+1) + x + 4(-2) = 0$. $2 + x - 8 = 0$. $x - 6 = 0$. $x = +6$. Therefore,the oxidation state of sulphur in $H_2SO_4$ is $+6$.

What is the oxidation state of sulphur in oil of vitriol?

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