What is the phase difference between two particles $25 \ m$ apart in a wave represented by the equation $y=0.03 \sin (\pi[2 t-0.01 x])$ traveling in a medium?

The equation of a wave is $y = 2 \sin \pi (0.5x - 200t)$,where $x$ and $y$ are expressed in $cm$ and $t$ in $sec$. The wave velocity is ...... $cm/sec$.

$A$ simple wave motion is represented by $y=5(\sin 4 \pi t+\sqrt{3} \cos 4 \pi t)$. Its amplitude is

When a wave propagating in one medium enters another medium,which of the following characteristics remains constant?

The rope shown at an instant is carrying a wave travelling towards the right,created by a source vibrating at a frequency $n$. Consider the following statements:
$I.$ The speed of the wave is $4n \times ab$
$II.$ The medium at $a$ will be in the same phase as $d$ after $\frac{4}{3n} \text{ s}$
$III.$ The phase difference between $b$ and $e$ is $\frac{3\pi}{2}$
Which of these statements are correct?

$A$ transverse wave is represented by $y = \frac{10}{\pi} \sin \left( \frac{2\pi}{T}t - \frac{2\pi}{\lambda}x \right)$. For what value of the wavelength is the wave velocity twice the maximum particle velocity (in $cm$)?