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(A) The reaction between acetaldehyde $(CH_3CHO)$ and semicarbazide $(H_2N-NHCONH_2)$ is a nucleophilic addition-elimination reaction.In this reaction

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$H_3C-CH=N-NH-C(=O)-NH_2$

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(A) The reaction between acetaldehyde $(CH_3CHO)$ and semicarbazide $(H_2N-NHCONH_2)$ is a nucleophilic addition-elimination reaction.In this reaction,the carbonyl oxygen of the acetaldehyde is replaced by the nitrogen atom of the semicarbazide,resulting in the formation of a semicarbazone derivative.The reaction is as follows:$CH_3CHO + H_2N-NHCONH_2 \rightarrow CH_3CH=N-NHCONH_2 + H_2O$The product formed is acetaldehyde semicarbazone,which corresponds to the structure $H_3C-CH=N-NH-C(=O)-NH_2$.

What is the product obtained in the reaction of acetaldehyde with semicarbazide?

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