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(B) The dehydration reaction of cane sugar (sucrose) with concentrated $H_2SO_4$ is given by:$C_{12}H_{22}O_{11} \xrightarrow{	ext{Conc. } H_2SO_4} 1

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$19.8$

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(B) The dehydration reaction of cane sugar (sucrose) with concentrated $H_2SO_4$ is given by:$C_{12}H_{22}O_{11} \xrightarrow{	ext{Conc. } H_2SO_4} 12C + 11H_2O$From the stoichiometry,$1 \ mol$ of $C_{12}H_{22}O_{11}$ yields $11 \ mol$ of $H_2O$.The molar mass of $C_{12}H_{22}O_{11} = (12 	imes 12) + (22 	imes 1) + (11 	imes 16) = 342 \ g/mol$.Number of moles of sugar $= \frac{34.2 \ g}{342 \ g/mol} = 0.1 \ mol$.Since $1 \ mol$ of sugar produces $11 \ mol$ of $H_2O$,then $0.1 \ mol$ of sugar produces $0.1 	imes 11 = 1.1 \ mol$ of $H_2O$.The mass of $1.1 \ mol$ of $H_2O = 1.1 \ mol 	imes 18 \ g/mol = 19.8 \ g$.

What is the quantity of water produced when $34.2 \ g$ of cane sugar is treated with concentrated $H_2SO_4$ under normal conditions of temperature and pressure (in $g$)?

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