What is the quotient when x^3-5x^2+2x+7 is di | vedclass

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(D) To find the quotient,we perform polynomial long division of $x^3-5x^2+2x+7$ by $(x-1)$:$1$. Divide the first term $x^3$ by $x$ to get $x^2$.$2$. M

Vedclass · Accepted Answer

$x^2-4x-2$

Vedclass · Answer

(D) To find the quotient,we perform polynomial long division of $x^3-5x^2+2x+7$ by $(x-1)$:$1$. Divide the first term $x^3$ by $x$ to get $x^2$.$2$. Multiply $x^2$ by $(x-1)$ to get $x^3-x^2$. Subtract this from the original polynomial to get $-4x^2+2x+7$.$3$. Divide $-4x^2$ by $x$ to get $-4x$.$4$. Multiply $-4x$ by $(x-1)$ to get $-4x^2+4x$. Subtract this from the current remainder to get $-2x+7$.$5$. Divide $-2x$ by $x$ to get $-2$.$6$. Multiply $-2$ by $(x-1)$ to get $-2x+2$. Subtract this from $-2x+7$ to get a remainder of $5$.Thus,the quotient is $x^2-4x-2$.Therefore,option $(D)$ is correct.

What is the quotient when $x^3-5x^2+2x+7$ is divided by $(x-1)$?

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