What is the ratio of the rate of diffusion of | vedclass

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(A) According to Graham's Law of Diffusion,the rate of diffusion $(r)$ is inversely proportional to the square root of the molar mass $(M)$: $\frac{r_

Vedclass · Accepted Answer

$1:4$

Vedclass · Answer

(A) According to Graham's Law of Diffusion,the rate of diffusion $(r)$ is inversely proportional to the square root of the molar mass $(M)$: $\frac{r_1}{r_2} = \sqrt{\frac{M_2}{M_1}}$.For oxygen $(O_2)$,$M_1 = 32 \ g/mol$.For hydrogen $(H_2)$,$M_2 = 2 \ g/mol$.Substituting the values: $\frac{r_{O_2}}{r_{H_2}} = \sqrt{\frac{2}{32}} = \sqrt{\frac{1}{16}} = \frac{1}{4}$.Therefore,the ratio is $1:4$.

What is the ratio of the rate of diffusion of oxygen $(O_2)$ and hydrogen $(H_2)$?

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