What is the ratio of the rate of diffusion of | vedclass

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(A) According to Graham's law of diffusion,the rate of diffusion $(r)$ is inversely proportional to the square root of the molar mass $(M)$: $r \propt

Vedclass · Accepted Answer

$1 : 4$

Vedclass · Answer

(A) According to Graham's law of diffusion,the rate of diffusion $(r)$ is inversely proportional to the square root of the molar mass $(M)$: $r \propto \frac{1}{\sqrt{M}}$.Therefore,the ratio of the rate of diffusion of $O_2$ to $H_2$ is given by: $\frac{r_{O_2}}{r_{H_2}} = \sqrt{\frac{M_{H_2}}{M_{O_2}}}$.The molar mass of $O_2$ is $32 \ g/mol$ and the molar mass of $H_2$ is $2 \ g/mol$.Substituting these values: $\frac{r_{O_2}}{r_{H_2}} = \sqrt{\frac{2}{32}} = \sqrt{\frac{1}{16}} = \frac{1}{4}$.Thus,the ratio is $1 : 4$.

What is the ratio of the rate of diffusion of oxygen $(O_2)$ to hydrogen $(H_2)$?

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