(C) In the estimation of $C$ and $H$,the organic compound is burnt in a stream of pure oxygen or air. Since the amount of $H_2O$ produced is determine

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To ensure that the moisture present in the air does not affect the weight of $H_2O$ produced.

(C) In the estimation of $C$ and $H$,the organic compound is burnt in a stream of pure oxygen or air. Since the amount of $H_2O$ produced is determined by weighing,it is essential that the air used for combustion is free from moisture. If the air is not dry,it will contain $H_2O$ vapor,which will be absorbed by the $CaCl_2$ tube,leading to an incorrect (higher) mass of $H_2O$ and thus an inaccurate estimation of hydrogen.

Class 11 Chemistry 3 Organic Chemistry: Purification and Characterisation Quantitative Analysis

Easy

What is the reason for passing dry air through the combustion tube during the estimation of $C$ and $H$?

A
To provide oxygen for combustion.
B
To remove moisture from the sample.
C
To ensure that the moisture present in the air does not affect the weight of $H_2O$ produced.
D
To increase the rate of combustion.

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Class 11

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Chapter

3 Organic Chemistry: Purification and Characterisation

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Quantitative Analysis

Match column $-I$ and column $-II$ with the correct relation:

Column $-I$ Column $-II$

$(i)$ Dumas method $(a)$ Absorption of $NH_3$ in $H_2SO_4$

$(ii)$ Kjeldahl's method $(b)$ $BaCl_2$ by added $BaSO_4$

$(iii)$ Carius method $(c)$ Mixture of Magnesia

$(iv)$ Estimation of phosphorus $(d)$ $N_2$

Column $-I$	Column $-II$
$(i)$ Dumas method	$(a)$ Absorption of $NH_3$ in $H_2SO_4$
$(ii)$ Kjeldahl's method	$(b)$ $BaCl_2$ by added $BaSO_4$
$(iii)$ Carius method	$(c)$ Mixture of Magnesia
$(iv)$ Estimation of phosphorus	$(d)$ $N_2$

Easy

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In Dumas's method for estimation of nitrogen,$0.25 \, g$ of an organic compound gave $40 \, mL$ of nitrogen collected at $300 \, K$ temperature and $725 \, mm$ pressure. If the aqueous tension at $300 \, K$ is $25 \, mm,$ the percentage of nitrogen in the compound is

DifficultNEET 2015

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When $1 \ g$ of compound $(X)$ is subjected to Kjeldahl's method for the estimation of nitrogen, $15 \ mL$ of $1 \ M$ $H_2SO_4$ was neutralized by the ammonia evolved. The percentage of nitrogen in compound $(X)$ is:

DifficultJEE MAIN 2026

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$58 \ mL$ of $\frac{N}{5} \ H_2SO_4$ are used to neutralize ammonia given by $1 \ g$ of an organic compound. The percentage of nitrogen in the compound is:

Medium

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In the Kjeldahl's method for estimation of nitrogen present in a soil sample,ammonia evolved from $0.75 \ g$ of sample neutralized $10 \ mL$ of $1 \ M \ H_2SO_4$. The percentage of nitrogen in the soil is (in $.33$)

DifficultNEET 2014

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What is the reason for passing dry air through the combustion tube during the estimation of $C$ and $H$?

Similar Questions

Match column $-I$ and column $-II$ with the correct relation: Column $-I$ Column $-II$ $(i)$ Dumas method $(a)$ Absorption of $NH_3$ in $H_2SO_4$ $(ii)$ Kjeldahl's method $(b)$ $BaCl_2$ by added $BaSO_4$ $(iii)$ Carius method $(c)$ Mixture of Magnesia $(iv)$ Estimation of phosphorus $(d)$ $N_2$

In Dumas's method for estimation of nitrogen,$0.25 \, g$ of an organic compound gave $40 \, mL$ of nitrogen collected at $300 \, K$ temperature and $725 \, mm$ pressure. If the aqueous tension at $300 \, K$ is $25 \, mm,$ the percentage of nitrogen in the compound is

When $1 \ g$ of compound $(X)$ is subjected to Kjeldahl's method for the estimation of nitrogen, $15 \ mL$ of $1 \ M$ $H_2SO_4$ was neutralized by the ammonia evolved. The percentage of nitrogen in compound $(X)$ is:

$58 \ mL$ of $\frac{N}{5} \ H_2SO_4$ are used to neutralize ammonia given by $1 \ g$ of an organic compound. The percentage of nitrogen in the compound is:

In the Kjeldahl's method for estimation of nitrogen present in a soil sample,ammonia evolved from $0.75 \ g$ of sample neutralized $10 \ mL$ of $1 \ M \ H_2SO_4$. The percentage of nitrogen in the soil is (in $.33$)

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