What is the solubility product (K_{sp}) of a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Step $1$: Calculate the molar solubility $(S)$ of the salt.$S = \frac{	ext{moles of solute}}{	ext{volume of solution in L}} = \frac{10^{-4} 	ex

Vedclass · Accepted Answer

$1 	imes 10^{-6}$

Vedclass · Answer

(B) Step $1$: Calculate the molar solubility $(S)$ of the salt.$S = \frac{	ext{moles of solute}}{	ext{volume of solution in L}} = \frac{10^{-4} 	ext{ mol}}{0.1 	ext{ L}} = 10^{-3} 	ext{ M}$.Step $2$: For a binary salt $BA$, the dissociation is $BA(s) ightleftharpoons B^+(aq) + A^-(aq)$.Step $3$: The solubility product expression is $K_{sp} = [B^+][A^-] = S 	imes S = S^2$.Step $4$: Substitute the value of $S$: $K_{sp} = (10^{-3})^2 = 10^{-6}$.

What is the solubility product $(K_{sp})$ of a binary sparingly soluble salt $BA$ if a $100 \text{ mL}$ saturated solution of the salt contains $10^{-4} \text{ moles}$ at room temperature?

Similar Questions

Derive the equation for the solubility and solubility product of a sparingly soluble salt $M_{x}X_{y}$.

Consider the following salts: $NaCl, HgCl_{2}, Hg_{2}Cl_{2}, CuCl_{2}, CuCl$ and $AgCl$. Identify the correct set of insoluble salts in water.

The solubility of $PbCl_2$ is

The solubility product of $Ag_{2}CrO_{4}$ is $32 \times 10^{-12}$. What is the concentration of $CrO_{4}^{2-}$ ions in that solution?

If the solubility product of $CuS$ is $9 \times 10^{-16}$,then what will be the maximum molarity of $CuS$ in an aqueous solution?

Vedclass Test Series

Exam Paper Generator

Online Exam Module