What is the total number of -OH groups presen | vedclass

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(D) nucleoside is formed by the combination of a pentose sugar and a nitrogenous base. In $DNA$,the sugar involved is $2$-deoxy-$D$-ribose. In $2$-deo

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(D) nucleoside is formed by the combination of a pentose sugar and a nitrogenous base. In $DNA$,the sugar involved is $2$-deoxy-$D$-ribose. In $2$-deoxy-$D$-ribose,the $-OH$ group at the $C-2$ position is replaced by a hydrogen atom. Therefore,the sugar has $-OH$ groups at the $C-3$ and $C-5$ positions. When the nitrogenous base attaches to the $C-1$ position of the sugar,the $-OH$ group at $C-1$ is removed. Thus,the resulting nucleoside (deoxyribonucleoside) contains two $-OH$ groups,one at the $C-3$ position and one at the $C-5$ position.

$A$. Adenine	$I$. Uracil structure
$B$. Cytosine	$II$. Thymine structure
$C$. Thymine	$III$. Adenine structure
$D$. Uracil	$IV$. Cytosine structure

What is the total number of $-OH$ groups present in a nucleoside involved in the formation of $DNA$?

Similar Questions

The nitrogenous base which differentiates $DNA$ from $RNA$ is:

Match List $-I$ with List $-II$.
$A$. Adenine $I$. Uracil structure
$B$. Cytosine $II$. Thymine structure
$C$. Thymine $III$. Adenine structure
$D$. Uracil $IV$. Cytosine structure

Choose the correct answer from the options given below:

According to Chargaff's rule,in a living system:

The $AT/GC$ ratio in human beings is (where $A = \text{adenine}$,$T = \text{thymine}$,$G = \text{guanine}$,$C = \text{cytosine}$)

Which of the following is not present in nucleic acids?

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