What is the total number of electrons present | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The electronic configuration of $O_2$ molecule is $(\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 (\sigma 2p_z)^2 (\pi 2p_x)^2 (\pi 2

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(C) The electronic configuration of $O_2$ molecule is $(\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 (\sigma 2p_z)^2 (\pi 2p_x)^2 (\pi 2p_y)^2 (\pi^* 2p_x)^1 (\pi^* 2p_y)^1$. Bonding molecular orbitals are those without an asterisk $(*)$. These are $(\sigma 1s)^2$,$(\sigma 2s)^2$,$(\sigma 2p_z)^2$,$(\pi 2p_x)^2$,and $(\pi 2p_y)^2$. Total number of electrons in bonding orbitals = $2 + 2 + 2 + 2 + 2 = 10$.

What is the total number of electrons present in bonding orbitals of $O_2$ molecule according to molecular orbital theory?

Similar Questions

Which of the following options represents the correct bond order?

Which of the following pictorial diagrams most correctly represents the $\pi^*$ ($\pi$-antibonding) molecular orbital between two atoms if the internuclear axis is taken to be in the $z$-direction?

The bond order of a molecule is given by:

According to the molecular orbital theory,the bond order in $C_2$ molecule is

How many electrons are present in the antibonding molecular orbitals of the $O_2$ molecule?

Vedclass Test Series

Exam Paper Generator

Online Exam Module