What is the total number of tetrahedral voids | vedclass

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(B) In a crystal lattice,the number of tetrahedral voids is twice the number of atoms present in the lattice. $1 \ mole$ of compound contains $6.022 \

Vedclass · Accepted Answer

$7.2264 	imes 10^{23}$

Vedclass · Answer

(B) In a crystal lattice,the number of tetrahedral voids is twice the number of atoms present in the lattice. $1 \ mole$ of compound contains $6.022 	imes 10^{23}$ atoms. $0.6 \ mole$ of compound contains $0.6 	imes 6.022 	imes 10^{23}$ atoms. Number of tetrahedral voids $= 2 	imes (	ext{Number of atoms}) = 2 	imes 0.6 	imes 6.022 	imes 10^{23}$. $= 1.2 	imes 6.022 	imes 10^{23} = 7.2264 	imes 10^{23}$ voids.

What is the total number of tetrahedral voids in $0.6 \ mole$ of a compound that forms a $hcp$ structure?

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