What is the unit digit in {(6374)^{1793} time | vedclass

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Question

(A) To find the unit digit of the expression $\{(6374)^{1793} 	imes (625)^{317} 	imes (341)^{491}\}$,we look at the unit digits of each base.$1$. Fo

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(A) To find the unit digit of the expression $\{(6374)^{1793} 	imes (625)^{317} 	imes (341)^{491}\}$,we look at the unit digits of each base.$1$. For $(6374)^{1793}$: The unit digit is $4$. Since the exponent $1793$ is odd,the unit digit of $(6374)^{1793}$ is $4$.$2$. For $(625)^{317}$: The unit digit is $5$. Any power of a number ending in $5$ always results in a unit digit of $5$.$3$. For $(341)^{491}$: The unit digit is $1$. Any power of a number ending in $1$ always results in a unit digit of $1$.Now,multiply these unit digits: $4 	imes 5 	imes 1 = 20$.The unit digit of the product $20$ is $0$.Therefore,the unit digit of the entire expression is $0$.

What is the unit digit in $\{(6374)^{1793} \times (625)^{317} \times (341)^{491}\}?$

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