(B) The lowest energy transition in the Balmer series occurs from $n_2 = 3$ to $n_1 = 2$. Using the Rydberg formula for wave number: $\overline{v} = R

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$R_H \left( \frac{5}{36} \right)$

(B) The lowest energy transition in the Balmer series occurs from $n_2 = 3$ to $n_1 = 2$. Using the Rydberg formula for wave number: $\overline{v} = R_H \left[ \frac{1}{n_1^2} - \frac{1}{n_2^2} \right]$. Substituting the values: $\overline{v} = R_H \left[ \frac{1}{2^2} - \frac{1}{3^2} \right]$. $\overline{v} = R_H \left[ \frac{1}{4} - \frac{1}{9} \right] = R_H \left[ \frac{9-4}{36} \right] = R_H \left( \frac{5}{36} \right)$.

Class 11 Chemistry Structure of Atom Atomic models and Planck's quantum theory

Medium

What is the wave number of the lowest energy transition in the Balmer series?

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A
$R_H \left( \frac{36}{5} \right)$
B
$R_H \left( \frac{5}{36} \right)$
C
$R_H \left( \frac{21}{100} \right)$
D
$R_H \left( \frac{100}{21} \right)$

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Structure of Atom

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Atomic models and Planck's quantum theory

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What is the wave number of the lowest energy transition in the Balmer series?

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