What is the volume of $n$ moles of gas? Derive the formula for the combined gas law.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Volume of $n$ moles of gas: According to the ideal gas equation,$pV = nRT$.
Therefore,$V = \frac{nRT}{p}$.
If the temperature $(T)$,pressure $(p)$,and amount of gas $(n)$ are held constant,the volume $(V)$ is determined by these parameters.
Combined Gas Law:
Starting from the ideal gas equation: $pV = nRT$.
Rearranging the terms,we get: $\frac{pV}{T} = nR$.
Since $n$ (number of moles) and $R$ (universal gas constant) are constants for a fixed amount of gas,we can write: $\frac{pV}{T} = \text{constant}$.
If the state of a fixed amount of gas changes from $(p_1, V_1, T_1)$ to $(p_2, V_2, T_2)$,then:
$\frac{p_1 V_1}{T_1} = \frac{p_2 V_2}{T_2}$.
This equation is known as the combined gas law.

Explore More

Similar Questions

Define the gas constant $R$ in terms of work.

When $48 \, L$ of dry $N_2$ gas is passed through $36 \, g$ of $H_2O$ at $27 \, ^oC$,the weight of water decreases by $1.20 \, g$. What is the vapor pressure of water in $atm$?

Difficult
View Solution

Find the gas,if its density at $273 \ K$ temperature and $76 \ cm \ Hg$ pressure is $1.94 \ g / dm^3$.

If pressure becomes double at the same absolute temperature on $2 \ L$ $CO_2$,then the volume of $CO_2$ becomes ............ $L$.

$3.4$ moles of an ideal gas occupies a volume of $68 \ mL$ at $300 \ K$. What would be the pressure of the gas? $(R = 8.314 \ J \ K^{-1} \ mol^{-1})$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo