What least number must be added to 1056 so th | vedclass

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(A) To find the least number to be added,first divide $1056$ by $23$.$1056 \div 23 = 45$ with a remainder.$1056 = 23 	imes 45 + 21$.The remainder is

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$2$

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(A) To find the least number to be added,first divide $1056$ by $23$.$1056 \div 23 = 45$ with a remainder.$1056 = 23 	imes 45 + 21$.The remainder is $21$.To make the number completely divisible by $23$,we need to add the difference between the divisor and the remainder to the original number.Required number to be added $= 23 - 21 = 2$.Therefore,adding $2$ to $1056$ gives $1058$,which is $23 	imes 46 = 1058$.

What least number must be added to $1056$ so that the sum is completely divisible by $23$?

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