What must be the molarity of $BaCl_2$ solution to have molar conductivity $240 \text{ }\Omega^{-1}\text{cm}^2\text{mol}^{-1}$ and conductivity $0.012 \text{ }\Omega^{-1}\text{cm}^{-1}$ at $25 \text{ }^\circ\text{C}$ (in M)?

The conductivity of a centimolar solution of $KCl$ at $298\text{ K}$ is $0.021\text{ }\Omega^{-1}\text{ cm}^{-1}$ and the resistance of the cell containing the solution at $298\text{ K}$ is $60\text{ }\Omega$. The value of the cell constant $(G^*)$ is (in $text{ cm}^{-1}$)

Given below are two statements:
Assertion $(A)$: Conductivity of an electrolyte decreases on dilution.
Reason $(R)$: On dilution,the number of ions per unit volume increases.
The correct answer is:

Explain Kohlrausch law of independent migration of ions.

$A$ conductivity cell containing $5 \times 10^{-4} \ M \ NaCl$ solution develops a resistance of $14000 \ \Omega$ at $25^{\circ} C$. Calculate the conductivity of the solution if the cell constant is $0.84 \ cm^{-1}$.

$A$ solution of concentration $C \ g \ equiv/L$ has a specific resistance $R$. The equivalent conductance of the solution is