What should be the order of arrangement of de-Broglie wavelength of an electron $(\lambda_{e})$,an $\alpha$-particle $(\lambda_{\alpha})$,and a proton $(\lambda_{p})$,given that all have the same kinetic energy?

• A
  $\lambda_{e} = \lambda_{p} > \lambda_{\alpha}$
• B
  $\lambda_{e} = \lambda_{p} = \lambda_{\alpha}$
• C
  $\lambda_{e} > \lambda_{p} > \lambda_{\alpha}$
• D
  $\lambda_{e} < \lambda_{p} < \lambda_{\alpha}$