What volume of ammonia is formed when 10 dm^ | vedclass

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(B) The balanced chemical equation for the reaction is:$N_{2(g)} + 3H_{2(g)} \longrightarrow 2NH_{3(g)}$According to Avogadro's law,at constant temper

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$20$

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(B) The balanced chemical equation for the reaction is:$N_{2(g)} + 3H_{2(g)} \longrightarrow 2NH_{3(g)}$According to Avogadro's law,at constant temperature and pressure,the volume ratio of gaseous reactants and products is equal to their stoichiometric mole ratio.From the equation,$1 \ volume$ of $N_2$ reacts with $3 \ volumes$ of $H_2$ to produce $2 \ volumes$ of $NH_3$.Given $10 \ dm^3$ of $N_2$ and $30 \ dm^3$ of $H_2$,the stoichiometric ratio is exactly $1:3$.Therefore,the volume of $NH_3$ formed is $2 	imes 10 \ dm^3 = 20 \ dm^3$.

What volume of ammonia is formed when $10 \ dm^3$ dinitrogen reacts with $30 \ dm^3$ dihydrogen at same temperature and pressure (in $dm^3$)?

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