What will be the effect on the fraction of mo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to the Arrhenius equation,$k = Ae^{-E_a/RT}$,the rate constant $k$ increases exponentially with an increase in temperature $T$. Addition

Vedclass · Accepted Answer

Both increase

Vedclass · Answer

(A) According to the Arrhenius equation,$k = Ae^{-E_a/RT}$,the rate constant $k$ increases exponentially with an increase in temperature $T$. Additionally,the fraction of molecules having energy equal to or greater than the activation energy $(E_a)$ is given by the Boltzmann factor $f = e^{-E_a/RT}$. As temperature $T$ increases,the value of $e^{-E_a/RT}$ increases,meaning a larger fraction of molecules possess sufficient energy to cross the activation energy barrier. Therefore,both the fraction of molecules and the rate constant increase with an increase in temperature.

What will be the effect on the fraction of molecules and the rate constant on increasing temperature?

Similar Questions

What is the slope of the straight line for the graph drawn between $\ln k$ and $\frac{1}{T}$,where $k$ is the rate constant of a reaction at temperature $T$?

The energy of activation is

For a first order chemical reaction,

According to Arrhenius theory,the activation energy is

Vedclass Test Series

Exam Paper Generator

Online Exam Module