What will be the major product when 2-methylb | vedclass

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(B) In the presence of sunlight,the reaction proceeds via a free radical mechanism. Bromination is highly selective,and the stability of the intermedi

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$2-$bromo$-2-$methylbutane

Vedclass · Answer

(B) In the presence of sunlight,the reaction proceeds via a free radical mechanism. Bromination is highly selective,and the stability of the intermediate free radical determines the major product. The $3^{\circ}$ free radical is more stable than $1^{\circ}$ or $2^{\circ}$ free radicals. Therefore,the hydrogen atom attached to the $C-2$ carbon is replaced by bromine to form $2-$bromo$-2-$methylbutane as the major product.

What will be the major product when $2-$methylbutane undergoes bromination in the presence of light?

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