What will be the amount of DNA in meiosis II | vedclass

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(C) In the $G_1$ phase,the meiocyte is diploid $(2n)$ and contains $2c$ amount of $DNA$. Given that $2c = 30 \; pg$.During the $S$ phase,$DNA$ replica

Vedclass · Accepted Answer

$15$

Vedclass · Answer

(C) In the $G_1$ phase,the meiocyte is diploid $(2n)$ and contains $2c$ amount of $DNA$. Given that $2c = 30 \; pg$.During the $S$ phase,$DNA$ replication occurs,doubling the $DNA$ content to $4c$ $(60 \; pg)$.After meiosis $I$,two daughter cells are formed,each with $n$ chromosomes and $2c$ amount of $DNA$ $(30 \; pg)$.After meiosis $II$,each of these cells divides again to form four haploid daughter cells,each containing $n$ chromosomes and $c$ amount of $DNA$.Since $2c = 30 \; pg$,then $c = 15 \; pg$.Therefore,the amount of $DNA$ in each meiosis $II$ product is $15 \; pg$.

List-$I$ (Phase of meiosis)	List-$II$ (Event that occurs)
$1$. Prophase $I$	Crossing over occurs
$2$. Metaphase $I$	Sister chromatids migrate to opposite poles
$3$. Anaphase $I$	Homologous chromosomes line up at the equator in pairs

What will be the amount of $DNA$ in meiosis $II$ products if a meiocyte contains $30 \; pg$ $DNA$ in the $G_1$ phase (in $; pg$)?

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