What will be the conjugate acid-base pair in | vedclass

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(B) conjugate acid-base pair differs by a single proton $(H^{+})$. In the reaction $HCl_{(aq)} + H_2O_{(aq)} \rightleftharpoons H_3O^{+}_{(aq)} + Cl^{

Vedclass · Accepted Answer

$HCl$ and $Cl^{-}$,$H_3O^{+}$ and $H_2O$

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(B) conjugate acid-base pair differs by a single proton $(H^{+})$. In the reaction $HCl_{(aq)} + H_2O_{(aq)} \rightleftharpoons H_3O^{+}_{(aq)} + Cl^{-}_{(aq)}$: $1$. $HCl$ acts as an acid and loses a proton to form its conjugate base,$Cl^{-}$. Thus,$(HCl, Cl^{-})$ is a conjugate acid-base pair. $2$. $H_2O$ acts as a base and accepts a proton to form its conjugate acid,$H_3O^{+}$. Thus,$(H_3O^{+}, H_2O)$ is a conjugate acid-base pair.

Acid	$HF$	$HCl$	$HBr$	$HI$
$K_a$	$7.2 \times 10^{-4}$	$1 \times 10^6$	$1 \times 10^9$	$3 \times 10^{11}$

What will be the conjugate acid-base pair in the reaction $HCl_{(aq)} + H_2O_{(aq)} \rightleftharpoons H_3O^{+}_{(aq)} + Cl^{-}_{(aq)}$?

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