What will be the name of the product formed upon the ammonolysis of benzyl chloride followed by the reaction of the resulting amine with two moles of $CH_3Cl$?

Given below are two statements :
Statement $I$: Aniline reacts with conc. $H_2SO_4$ followed by heating at $453-473 \ K$ to give $p$-aminobenzene sulphonic acid (sulphanilic acid). This compound contains both nitrogen and sulphur,and thus it gives a blood red colour in the 'Lassaigne's test' due to the formation of ferric thiocyanate,$[Fe(SCN)]^{2+}$.
Statement $II$: In Friedel-Craft's alkylation and acylation reactions,aniline forms a salt with the $AlCl_3$ catalyst. Due to this,the nitrogen atom of aniline acquires a positive charge and acts as a deactivating group,preventing further reaction.
In the light of the above statements,choose the correct answer from the options given below :

Benzenediazonium chloride on reaction with phenol in weakly basic medium gives

Yellow dye can be prepared by a coupling reaction of benzene diazonium chloride in acidic medium with $X$. Identify $X$ from the following.

The major product $Z$ obtained in the following reaction scheme is

The amine which does not react with chloroform and ethanolic potassium hydroxide is