What will be the product in the following reaction?
$1$-chloro-$1$-methylcyclohexane $\xrightarrow{H_2O}$ ?

The major product obtained when this substrate is subjected to $E_2$ reaction under the treatment of potassium $tert$-butoxide is:

What is the product of the following reaction?

For the following compounds,the correct statement$(s)$ with respect to nucleophilic substitution reactions is(are):
$I$: Benzyl bromide $(C_6H_5CH_2Br)$
$II$: Cyclohexylmethyl bromide $(C_6H_{11}CH_2Br)$
$III$: tert-Butyl bromide $((CH_3)_3CBr)$
$IV$: $1-$Phenylethyl bromide $(C_6H_5CH(CH_3)Br)$
$A$. $I$ and $III$ follow $S_{N}1$ mechanism
$B$. $I$ and $II$ follow $S_{N}2$ mechanism
$C$. Compound $IV$ undergoes inversion of configuration
$D$. The order of reactivity for $I$,$III$ and $IV$ is: $IV > I > III$

In $S_N2$ reactions,the correct order of reactivity for the following compounds: $CH_3Cl$,$CH_3CH_2Cl$,$(CH_3)_2CHCl$,and $(CH_3)_3CCl$ is:

Reaction of $(R)-2$-butanol with $p$-toluenesulphonyl chloride in pyridine followed by $LiBr$ gives: