What will be the volume of O_2 gas at STP whi | vedclass

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(B) The balanced chemical equation for the thermal decomposition of $KClO_3$ is: $2 KClO_3 \rightarrow 2 KCl + 3 O_2$ First,calculate the mass of pure

Vedclass · Accepted Answer

$6.72$

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(B) The balanced chemical equation for the thermal decomposition of $KClO_3$ is: $2 KClO_3 ightarrow 2 KCl + 3 O_2$ First,calculate the mass of pure $KClO_3$: Mass $= 30.62 \ g 	imes \frac{80}{100} = 24.5 \ g$ Calculate the number of moles of $KClO_3$: Molar mass of $KClO_3 = 39.1 + 35.5 + 3 	imes 16 = 122.6 \ g/mol$ Moles of $KClO_3 = \frac{24.5 \ g}{122.6 \ g/mol} \approx 0.2 \ mol$ From the stoichiometry,$2 \ mol$ of $KClO_3$ produces $3 \ mol$ of $O_2$. Therefore,$0.2 \ mol$ of $KClO_3$ produces: Moles of $O_2 = \frac{3}{2} 	imes 0.2 = 0.3 \ mol$ At $STP$,the volume of $1 \ mol$ of gas is $22.4 \ L$. Volume of $O_2 = 0.3 \ mol 	imes 22.4 \ L/mol = 6.72 \ L$.

What will be the volume of $O_2$ gas at $STP$ which is obtained by thermal decomposition of $30.62 \ g$ $KClO_3$,with $80\%$ purity?

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